**font-family: sans-serif**
From the fundamental
theorem of arithmetic, we know that any integer greater than 1 can
be expressed as a unique product of primes. A corollary of this theorem
is:

Any positive integer N > 1 can be written uniquely
in a canonical form N =
p_{1}^{k1}p_{2}^{k2}
… p_{n}^{kn} where, each k_{i}
is a positive integer and each p_{i} is a prime for positive
integers i, 1 ≤ i ≤ n.

Euler's theorem states that if n is a positive integer and a is a
positive integer coprime to n, then

a^{φ(n)} ≡ 1 (mod n)

The integral of a function f over the interval [a, b] can
be calculated by finding an antiderivative F of f:

∫_{a}^{b} f(x) dx = F(a) - b(a)

where

^{d}⁄

_{dx} F(x) = f(x)

**font-family: arial**
From the fundamental
theorem of arithmetic, we know that any integer greater than 1 can
be expressed as a unique product of primes. A corollary of this theorem
is:

Any positive integer N > 1 can be written uniquely in a
canonical form N =
p_{1}^{k1}p_{2}^{k2}
… p_{n}^{kn} where, each k_{i}
is a positive integer and each p_{i} is a prime for positive
integers i, 1 ≤ i ≤ n.

Euler's theorem states that if n is a positive integer and
a is a positive integer coprime to n, then

a^{φ(n)} ≡ 1 (mod n)

The integral of a function f over the interval [a, b] can
be calculated by finding an antiderivative F of f:

∫_{a}^{b} f(x) dx = F(a) - b(a)

where

^{d}⁄

_{dx} F(x) = f(x)

**font-family: helvetica**
From the fundamental
theorem of arithmetic, we know that any integer greater than 1 can
be expressed as a unique product of primes. A corollary of this theorem
is:

Any positive integer N > 1 can be written uniquely in a
canonical form N =
p_{1}^{k1}p_{2}^{k2}
… p_{n}^{kn} where, each k_{i}
is a positive integer and each p_{i} is a prime for positive
integers i, 1 ≤ i ≤ n.

Euler's theorem states that if n is a positive integer and
a is a positive integer coprime to n, then

a^{φ(n)} ≡ 1 (mod n)

The integral of a function f over the interval [a, b] can
be calculated by finding an antiderivative F of f:

∫_{a}^{b} f(x) dx = F(a) - b(a)

where

^{d}⁄

_{dx} F(x) = f(x)

**font-family: 'trebuchet
ms'**
From the fundamental
theorem of arithmetic, we know that any integer greater than 1 can
be expressed as a unique product of primes. A corollary of this theorem
is:

Any positive integer N > 1 can be written uniquely in a
canonical form N =
p_{1}^{k1}p_{2}^{k2}
… p_{n}^{kn} where, each k_{i}
is a positive integer and each p_{i} is a prime for positive
integers i, 1 ≤ i ≤ n.

Euler's theorem states that if n is a positive integer and
a is a positive integer coprime to n, then

a^{φ(n)} ≡ 1 (mod n)

The integral of a function f over the interval [a, b] can
be calculated by finding an antiderivative F of f:

∫_{a}^{b} f(x) dx = F(a) - b(a)

where

^{d}⁄

_{dx} F(x) = f(x)

**font-family: georgia**
From the fundamental
theorem of arithmetic, we know that any integer greater than 1 can
be expressed as a unique product of primes. A corollary of this theorem
is:

Any positive integer N > 1 can be written uniquely in a
canonical form N =
p_{1}^{k1}p_{2}^{k2}
… p_{n}^{kn} where, each k_{i}
is a positive integer and each p_{i} is a prime for positive
integers i, 1 ≤ i ≤ n.

Euler's theorem states that if n is a positive integer and
a is a positive integer coprime to n, then

a^{φ(n)} ≡ 1 (mod n)

The integral of a function f over the interval [a, b] can
be calculated by finding an antiderivative F of f:

∫_{a}^{b} f(x) dx = F(a) - b(a)

where

^{d}⁄

_{dx} F(x) = f(x)

**font-family: monospace**
From the fundamental
theorem of arithmetic, we know that any integer greater than 1 can
be expressed as a unique product of primes. A corollary of this theorem
is:

Any positive integer N > 1 can be written uniquely in a
canonical form N =
p_{1}^{k1}p_{2}^{k2}
… p_{n}^{kn} where, each k_{i}
is a positive integer and each p_{i} is a prime for positive
integers i, 1 ≤ i ≤ n.

Euler's theorem states that if n is a positive integer and
a is a positive integer coprime to n, then

a^{φ(n)} ≡ 1 (mod n)

The integral of a function f over the interval [a, b] can
be calculated by finding an antiderivative F of f:

∫_{a}^{b} f(x) dx = F(a) - b(a)

where

^{d}⁄

_{dx} F(x) = f(x)

**font-family:
'bistream sans vera mono'**
From the fundamental
theorem of arithmetic, we know that any integer greater than 1 can
be expressed as a unique product of primes. A corollary of this theorem
is:

Any positive integer N > 1 can be written uniquely in a
canonical form N =
p_{1}^{k1}p_{2}^{k2}
… p_{n}^{kn} where, each k_{i}
is a positive integer and each p_{i} is a prime for positive
integers i, 1 ≤ i ≤ n.

Euler's theorem states that if n is a positive integer and
a is a positive integer coprime to n, then

a^{φ(n)} ≡ 1 (mod n)

The integral of a function f over the interval [a, b] can
be calculated by finding an antiderivative F of f:

∫_{a}^{b} f(x) dx = F(a) - b(a)

where

^{d}⁄

_{dx} F(x) = f(x)